Q. 184.0( 9 Votes )

# Solve the following quadratic equations by factorization:

Answer :

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

⇒ 4x^{2} + 2(a + b)x – 2(a – b)x – (a – b)(a + b) = 0

⇒ 2x(2x + a + b) – (a – b)(2x – (a + b)) = 0

⇒ (2x – (a – b))(2x + a + b) = 0

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Bonus Questions on Solutions of Quadratic Equations31 mins

Get To Know About Quadratic Formula42 mins

Smart Revision | Quadratic Equations53 mins

Quiz | Knowing the Nature of Roots44 mins

Take a Dip Into Quadratic graphs32 mins

Foundation | Practice Important Questions for Foundation54 mins

Learn to Find Nature of Roots25 mins

Smart Revision | Learn to Find the Nature of RootsFREE Class

Nature of Roots of Quadratic Equations51 mins

Getting Familiar with Nature of Roots of Quadratic Equations51 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Find the roots of the following quadratic equations by factorisation:

KC Sinha - Mathematics

Find the roots of the following quadratic equations by factorisation:

2x^{2} — 5x + 3 = 0

4x^{2} — 2 (a^{2} + b^{2}) x + a^{2}b^{2} = 0

Find the roots of the following quadratic equations by factorisation:

3x^{2} — 14x — 5 = 0

36x^{2} — 12ax + (a^{2} — b^{2}) = 0