To find: The value of above equation.
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
apply the above formula and solve,
⇒ 9x2 – 3(a2 + b2)x + 3(a2 – b2)x – (a2 + b2)(a2 – b2) = 0
⇒ 3x(3x – (a2 + b2)) + (a2 – b2)(3x – (a2 + b2)) = 0
⇒ (3x + a2 – b2)(3x – (a2 + b2) = 0
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