Answer :

The system can be written as



A X = 0


Now, |A| = 2(– 3 + 2) – 3(3 + 6) – 1(1 + 3) = 0


|A| = – 2 – 27 – 4


|A| = – 33


Hence, the given system has only trivial solution given by x = y = z = 0


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