# AB, CD, PQ are perpendicular to BD. AB = x, CD = y and PQ = z prove that

Given, in Δ BCD, PQ || CD

….eq(1)

And in Δ ABD, PQ||AB

….eq(2)

Need to prove that

From eq(1) and eq(2) we have

1- [FROM EQ(1)]

1 = PQ()

…..eq(3)

Since, from the question we know that AB = X CD = Y and PQ = z

Substituting those values in eq(3) we get

Hence proved

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RELATED QUESTIONS :

In Δ PQR, ST is a line such that and also PST = PRQ. Prove that ΔPQR, is an isosceles triangle.

AP- Mathematics