Q. 5 A3.7( 3 Votes )

Find the number of terms in the following A.P.'s6, 3, 0, — 3,…..,–36

Here, a = 6 , d = 3 – 6 = –3 and l = –36

where l = a + (n – 1)d

–36 = 6 + (n – 1)(–3)

–36 = 6 –3n + 3

–36 = 9 – 3n

–36 – 9 = –3n

–45 = –3n

Hence, the number of terms in the given AP is 15

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