Q. 5 A3.7( 3 Votes )

Find the number of terms in the following A.P.'s

6, 3, 0, — 3,…..,–36

Answer :

Here, a = 6 , d = 3 – 6 = –3 and l = –36


where l = a + (n – 1)d


–36 = 6 + (n – 1)(–3)


–36 = 6 –3n + 3


–36 = 9 – 3n


–36 – 9 = –3n


–45 = –3n



Hence, the number of terms in the given AP is 15


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