# Diagonals AC and

Given, trapezium ABCD and diagonals AC and BD intersect each other.

Need to prove Let us consider Δ AOB and Δ DOC

AOB = DOC (vertically opposite angles)

by alternative interior angles we have

OAB = OCD

OBA = ODC

By AAA similarity we have in two triangles if the angles are equal, then sides opposite to the equal angles are in the same ratio (or proportional) and hence the triangles are similar.

Δ Aob Δ DOC Hence proved.

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