Q. 44.1( 327 Votes )

ABCD is a trapezi

Answer :

Let EF intersect DB at G

By converse of mid-point theorem, we know that a line drawn through the mid-point of any side of a triangle and parallel to another side, bisects the third side



In ΔABD,


EF || AB and E is the mid-point of AD


Therefore,


G will be the mid-point of DB


EF || AB and


AB || CD


EF || CD (Two lines parallel to the same line are parallel to each other)


In ΔBCD,


GF || CD and


G is the mid-point of line BD. Therefore, by using converse of mid-point theorem, F is the mid-point of BC

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