Q. 34.2( 33 Votes )

In a quadrilatera

Answer :


Given :- ABCD is a quadrilateral


OCB= OCD=C/2 [OC is bisector of C]


ODA= ODC=D/2 [OD is bisector of D]


Formula Used:- A+ B+ C+ D=360°


Solution :-


In Δ COD


OCD+ COD + ODC=180°


D/2 + C/2 + COD = 180°


( D+ C)/2 + COD = 180°


If;


A+ B+ C+ D=360°


C+ D=360° -( A+ B)


+ COD=180°


180° - + COD=180°


COD=


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