Q. 285.0( 3 Votes )

Find a if 5a + 2, 4a – I, a + 2 are in A.P.

Answer :

Let 5a + 2, 4a – 1, a + 2 are in AP


So, first term a = 5a + 2


d = 4a – 1 – 5a – 2 = – a – 3


n = 3


l = a + 2


So,


l = a + (n – 1)d


a + 2 =5a + 2 + (3 – 1)(–a – 3)


a + 2 – 5a – 2 = –3a – 9 + a + 3


– 4a = –2a – 6


– 4a + 2a = – 6


–2a = – 6


a = 3


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