# Find a if 5a + 2, 4a – I, a + 2 are in A.P.

Let 5a + 2, 4a – 1, a + 2 are in AP

So, first term a = 5a + 2

d = 4a – 1 – 5a – 2 = – a – 3

n = 3

l = a + 2

So,

l = a + (n – 1)d

a + 2 =5a + 2 + (3 – 1)(–a – 3)

a + 2 – 5a – 2 = –3a – 9 + a + 3

– 4a = –2a – 6

– 4a + 2a = – 6

–2a = – 6

a = 3

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Arithmetic Progression34 mins
Champ Quiz | Arithmetic Progression30 mins
Lets Check Your Knowledge in A.P.49 mins
NCERT | Fundamental Theorem Of Arithmetic45 mins
Fundamental Theorem of Arithmetic- 143 mins
Quiz on Arithmetic Progression Quiz32 mins
Arithmetic progression: Previous Year NTSE Questions34 mins
Get to Know About Geometric Progression41 mins
NCERT | Solving Questions on Introduction of A.P42 mins
Arithmetic Progression Tricks and QUIZ37 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses