Answer :

GIVEN : diameter of cylindrical bowl = 7cm

Radius of cylinder “r” = 3.5cm

Height upto which the soup is filled “h” = 4cm

No. of patients daily = 250

we take π =

TO FIND : quantity of soup to be prepared daily in the hospital to serve 250 patients = ?

PROCEDURE :

Volume of a cylindrical bowl “V” = π r^{2}h

Putting the values in the above formula, we get

V = × (3.5)^{2} × 4

V = ×3.5× 3.5× 4

= ×3.5×4

= 22× 3.5× 2

= 154cm^{3}

∴ volume of 1 bowl = 154cm^{3}

⇒ volume of 250 bowls = 250 × 154cm^{3} = 38500cm^{3}

Quantity of soup in the 250 bowls = 38500 × litres

{∵ 1litre = 1000cm^{3})

Quantity of soup in the 250 bowls = litres = 38.5 litres.

∴ Quantity of soup in the 250 bowls is 38.5 litres.

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