# Find the 10th term of the A.P. whose 7th and 12th terms are 34 and 64 respectively.

We have

a7 = a + (7 – 1)d = a + 6d = 34 …(1)

and a12 = a + (12 – 1)d = a + 11d = 64 …(2)

Solving the pair of linear equations (1) and (2), we get

a + 6d – a – 11d = 34 – 64

– 5d = –30

d = 6

Putting the value of d in eq (1), we get

a + 6(6) = 34

a + 36 = 34

a = –2

Hence, the required AP is –2, 4, 10, 16,…

Now, we to find the 10th term

So, an = a + (n – 1)d

a10 = –2 + (10 – 1)6

a10 = –2 + 9 × 6

a10 = 52

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Arithmetic Progression34 mins
Champ Quiz | Arithmetic Progression30 mins
Lets Check Your Knowledge in A.P.49 mins
NCERT | Fundamental Theorem Of Arithmetic45 mins
Quiz on Arithmetic Progression Quiz32 mins
Fundamental Theorem of Arithmetic- 143 mins
Arithmetic progression: Previous Year NTSE Questions34 mins
Get to Know About Geometric Progression41 mins
NCERT | Solving Questions on Introduction of A.P42 mins
Arithmetic Progression Tricks and QUIZ37 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses