Q. 133.8( 12 Votes )

# Prove that:</

Answer :

Take L.H.S.        {sin (-A) = -sin A & cos (-A) = cos A}       = cot C

= R.H.S.

Hence Proved

ii. Take L.H.S.:

sin(B– C)cos(A – D) + sin(C – A)cos(B – D) + sin(A – B)cos(C – D)

Multiplying & Dividing by 2: { 2 sin A cos B = sin (A + B) + sin (A – B)}    {sin (-A) = -sin A}  = 0

= R.H.S.

Hence Proved

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