Q. 13.5( 91 Votes )

Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y.

Answer :

It is given that of circle, 4x2 + 4y2 = 9 and parabola x2 = 4y.

On solving the above two equations, we get the point of intersection

We can see that the required area is symmetrical about y axis.

Thus, Area OBCDO = 2 × Area OBCO

Let us draw BM perpendicular to OA.

The coordinates of M are (, 0).

Then, Area OBCO = Area OABCO – Area OABO

Therefore, the required area OBCDO is


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