Answer :

A =

|A| = 3(3 – 0) + 4(2 – 5) + 2(0 – 3)


= 9 – 12 – 6


= – 9


Now, the cofactors of A


C11 = (– 1)1 + 1 3 – 0 = 3


C21 = (– 1)2 + 1 – 4 – 0 = 4


C31 = (– 1)3 + 1 – 20 – 6 = – 26


C12 = (– 1)1 + 2 2 – 5 = 3


C22 = (– 1)2 + 1 3 – 2 = 1


C32 = (– 1)3 + 1 15 – 4 = – 11


C13 = (– 1)1 + 2 0 – 3 = – 3


C23 = (– 1)2 + 1 0 + 4 = – 4


C33 = (– 1)3 + 1 9 + 8 = 17


adj A =


A – 1 =


A – 1 =


Now the given equation can be written as:



A X B


Or, X = A – 1B


=



X =


X =


Hence, x = 3,y = 2 and z = – 1


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