Answer :

i. Take L.H.S


sin A sin (B – C) + sin B sin (C – A) + sin C sin (A – B)


Multiplying & Dividing by 2:



{ 2 sin A sin B = cos (A – B) – cos (A + B)}





= 0


= R.H.S


Hence Proved


ii. sin (B – C) cos (A – D) + sin (C – A) cos(B – D) + sin(A – B) cos(C – D) = 0


Answer:


Take L.H.S


sin (B – C) cos(A – D) + sin (C – A) cos(B – D) + sin(A – B) cos(C – D)


Multiplying & Dividing by 2:



{ 2 sin A cos B = sin (A + B) + sin (A – B)}






= 0


= R.H.S


Hence Proved


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Prove that :
<
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that :
<
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics

Prove that:
</
RD Sharma - Mathematics