Answer :

__Given:-__ ABCD is a rectangle

__Formula used:__- All angles of rectangle are 90°

In right angle triangle

Pythagoras theorem a^{2}+b^{2}=c^{2}

Sin(θ)=

__Solution:-__

In ΔACD

∠ D=90° [All angles of rectangle are 90° ]

∠ ACD=θ_{1}

And; Sin(θ_{1}) = =

θ_{1}=arc sin()

∠ DAC=θ_{2}

And; Sin(θ_{2}) = =

θ_{1}=arc sin()

__Conclusion:-__

The angles of Δ ACD are :-

∠ D=90°

∠ DAC=arc sin()

∠ ACD=arc sin()

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