Q. 124.1( 10 Votes )

The diagonals AC A. 24°

B. 86°

C. 38°

D. 32°

Answer :

Given: AOB = 70°

DAC = 32°



AD BC and AC is transversal


ACB = 32°


Now,


AOB + BOC = 180°


70° + BOC = 180°


⇒ ∠BOC = 180° - 70°


⇒ ∠BOC = 110°


Sum of all angles of a triangle = 180°


⇒ ∠BOC + BCO + OBC = 180°


110° + 32°+ OBC = 180°


142°+ OBC = 180°


⇒ ∠OBC = 180° - 142°


⇒ ∠OBC = 38°


Hence, DBC = 38°

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