Q. 96 B4.3( 3 Votes )

# Express as a power of a rational number with negative exponent.

(2^{5} ÷ 2^{8}) × 2^{–7}

Answer :

using laws of exponents ,a^{m} × a^{n} = a^{(m+n)}

And , a^{m} ÷ a^{n} = a^{(m-n)}

We have , (2^{5} ÷ 2^{8}) = 2^{(5-8)}= 2^{-3}

Now , 2^{-3} × 2^{–7}= 2^{(-3)+(-7)}= 2^{-10}

∴ (2^{5} ÷ 2^{8}) × 2^{–7}= 2^{-10}

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