If one angle of a parallelogram is 36° less than the twice its adjacent angles, then find the angles of the parallelogram.

Sum of adjacent angles of parallelogram = 180°

Given:

One angle of Parallelogram = 2 (adjacent angle) – 36°

Let the angle of parallelogram be x

Sum of adjacent angles of parallelogram = 180°

2x +x + 36° = 180°

3x = 180° – 36°

3x = 144°

x = 48°

Now from the diagram, we know that,

∠A = 48°

∠B = 180° – 48° = 132°

∠C = ∠A = 48°

∠D = ∠B = 132°

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