Q. 177 E3.7( 3 Votes )

# Find x.

2^{3x} = 8^{2x+1}

Answer :

The above given equation can also be written as,

2^{3x} = ((2)^{3})^{2x + 1} ∵ 2^{3} = 8

As we know by the laws of exponent, that,

(a^{m})^{n} = a^{mn}

⇒ 2^{3x} = 2^{3(2x + 1)}

As the bases are same so the exponents can be equated,

⇒ 3x = 3(2x + 1)

⇒ x = 2x + 1

⇒ x = -1

∴ Value of x =-1

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