Q. 1083.8( 4 Votes )
Express the product of 3.2 × 106 and 4.1 × 10–1 in the standard form.
Answer :
Given that, to find the product of 3.2 × 106 and 4.1 × 10–1
Product of 3.2 × 106 and 4.1 × 10–1 = (3.2 × 106)( 4.1 × 10–1)
= (3.2 × 4.1) × 106 × 10-1
Using the law of exponent,
⇒ 13.12 × 105
= 1.312 × 105 × 101
= 1.312 × 106
∴ The product of 3.2 × 106 and 4.1 × 10–1 in the standard form is 1.312 × 106.
Rate this question :






















Express the product of 3.2 × 106 and 4.1 × 10–1 in the standard form.
NCERT - Mathematics ExemplarSimplify:
Out of the four options, only one is correct. Write the correct answer.
3–2 can be written as
NCERT - Mathematics ExemplarOut of the four options, only one is correct. Write the correct answer.
The value of is
Express 16–2 as a power with the base 2.
NCERT - Mathematics ExemplarExpress as a power of a rational number with negative exponent.
(25 ÷ 28) × 2–7
NCERT - Mathematics ExemplarFill in the blanks to make the statements true.
By solving (60 – 70) × (60 + 70) we get ________.
NCERT - Mathematics ExemplarFill in the blanks to make the statements true.
The value of [2–1 × 3–1]–1 is _________.
NCERT - Mathematics ExemplarFill in the blanks to make the statements true.
The value for (–7)6 ÷ 76 is _________.
NCERT - Mathematics Exemplar