Q. 1045.0( 2 Votes )

# Find the multiplicative inverse of (–7)^{–2} ÷ (90)^{–1}.

Answer :

Remember, a is called multiplicative inverse of b, if a × b = 1.

∴ (–7)^{–2} ÷ (90)^{–1} =

=

=

∵ (-a)^{m} = a^{m} , if m is an even number and (-a)^{m} =

Put b = in a × b = 1

a × = 1

∴

∴ The multiplicative inverse of (–7)^{–2} ÷ (90)^{–1} is

Rate this question :

Find the value of x–3 if x = (100)^{I–4} ÷ (100)^{0}.

Fill in the blanks to make the statements true.

The standard form for 0.000000008 is __________.

NCERT - Mathematics ExemplarFill in the blanks to make the statements true.

The standard form for 32,50,00,00,000 is __________.

NCERT - Mathematics ExemplarFill in the blanks to make the statements true.

The expression for 3^{5} with a negative exponent is _________.

Fill in the blanks to make the statements true.

The usual form for 2.3 × 10^{-10} is ____________.

Fill in the blanks to make the statements true.

a^{3} × a^{–10} = __________.

State whether the given statements are true (T)or false (F).

The value of is equal to 16.

NCERT - Mathematics ExemplarFill in the blanks to make the statements true.

To add the numbers given in standard form, we first convert them into numbers with __ exponents.

NCERT - Mathematics ExemplarFill in the blanks to make the statements true.

The value of 3 × 10^{-7} is equal to ________.

Fill in the blanks to make the statements true.

The multiplicative inverse of 10^{10} is __________.