Answer :

Given,

q^{2} – 10q + 21

Now first find the numbers whose-

Sum = - 10 and

Product = 21

Required numbers are 7 and 3,

So we get;

q^{2} – 10q + 21

= q^{2} – 7q – 3q + 21

= q(q – 7) – 3(q – 7)

= (q – 7)(q – 3)

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