Answer :
Given,
3y2 + 14y + 8
Now first find the numbers whose-
Sum = 14 and
Product = 3 × 8 = 24
Required numbers are 12 and 2,
So we get;
3y2 + 14y + 8 = 3y2 + 12y + 2y + 8
= 3y(y + 4) + 2(y + 4)
= (y + 4)(3y + 2)
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