Answer :
Given
z2 – 12z – 45
Now first find the numbers whose-
Sum = - 12 and
Product = - 45
Required numbers are 15 and 3,
So we get;
z2 – 12z – 45
= z2 – 15z + 3z - 45
= z(z – 15) + 3(z – 15)
= (z – 15)(z + 3)
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