Answer :

Given,

(l + m)^{2} – 4lm

By using the formula (a + b)^{2} = a^{2} + b^{2} + 2ab

We get,

(l + m)^{2} – 4lm = (l^{2} + m^{2} + 2lm) – 4lm

= l^{2} + m^{2} + 2lm – 4lm

= l^{2} + m^{2} – 2lm

= (l)^{2} + (m)^{2} - 2×l×m

= (l – m)^{2}

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Algebraic Identities - Mark your Weak Areas41 mins

Quiz | Important Questions on Factorisation35 mins

Quiz | Questions on Factorization41 mins

Champ Quiz | Division of Polynomials33 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Factorize each of the following expressions:

RD Sharma - Mathematics

Factorize each of the following expressions:

RD Sharma - Mathematics

ab - a - b + 1 = ?

RS Aggarwal - MathematicsFactorize each of the following expressions:

RD Sharma - Mathematics

Factorize:

x^{2} + x – 132

Factorize each of the following expressions:

RD Sharma - Mathematics

2x^{2} + 5x + 3=?

Factorize:

3m^{2} + 24m + 36

Factorize each of the following expressions:

RD Sharma - Mathematics