Q. 195.0( 28 Votes )

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Answer :

ab2 – bc2 – ab + c2


Let’s first arrange the terms in a suitable form;


ab2 – bc2 – ab + c2


= ab2 – ab – bc2 + c2


= (ab2 – ab) – (bc2 - c2)


= ab(b – 1) – c2(b - 1)


= (b – 1)(ab – c2)


So we get,


ab2 – bc2 – ab + c2 = (b – 1)(ab – c2)


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