Q. 195.0( 28 Votes )

# <span lang="EN-US

Answer :

ab2 – bc2 – ab + c2

Let’s first arrange the terms in a suitable form;

ab2 – bc2 – ab + c2

= ab2 – ab – bc2 + c2

= (ab2 – ab) – (bc2 - c2)

= ab(b – 1) – c2(b - 1)

= (b – 1)(ab – c2)

So we get,

ab2 – bc2 – ab + c2 = (b – 1)(ab – c2)

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