Q. 14.5( 51 Votes )

# Factories:

(i) 12x + 15

(ii) 14m – 21

(iii) 9n – 12n^{2}

Answer :

(i) 12x + 15

Taking 3 as common from the whole, we get,

12x + 15 = 3(4x + 5).

(ii) 14m – 21,

Taking 7 as common from the whole, we get,

14m – 21 = 7(2m – 3)

(iii) 9n – 12n^{2},

Taking 3n as common from the whole, we get,

9n – 12n^{2} = 3n (3 – 4n).

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Factories:

(i) 24x^{3} – 36x^{2}y

(ii) 10x^{3} – 15x^{2}

(iii) 36x^{3}y – 60x^{2}y^{3}z

Factories:

9a(3a – 5b) – 12a^{2}(3a – 5b)

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