Q. 144.0( 37 Votes )

# Evaluate

Let I =

Multiplying by 5 in numerator and denominator

I =

I =

I = I1 + I2

I1 =

Let 5x2 + 1 = t ….(i)

d(5x2 + 1) = dt

10x dx = dt …..(ii)

When x = 0; t = 5 × 02 + 1 = 1

When x = 1; t = 5 × 12 + 1 = 6

Substituting (i) and (ii) in I1

I1 = []

I1 =

I1 =

I2 = []

I2 =

I2 = 3/√5 tan-15

I = I1 + I2

I = 1/5 log 6 + 3/√5 tan-15

= 1/5 log 6 + 3/√5 tan-15

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