Q. 165.0( 1 Vote )

# Resolve each of t

Here, coefficient of a2 = 36, coefficient of a = 12bc and constant term = - 15b2c2

We shall now split up the coefficient of middle term i.e., 12bc into two parts whose sum is 12bc and product is 36 (-15b2c2) = - 500b2c2

So, we replace middle term 12abc = 30abc – 18abc

Thus, we have

36a2 –12abc– 15b2c2 = 36a2 + 30abc – 18abc – 15b2c2

= (6a + 5bc) (6a – 3bc)

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