Q. 9 O4.7( 3 Votes )

# In ΔABC, m∠

In Δ ABC, using Apolloneous Theorem, we know that,

For AD to be the median, we have,

AB2 + AC2 = 2(AD2 + BD2)

BC2 = 2 (36 + BD2)

4BD2 = 72 + 2BD2

2BD2 = 72

BD2 = 36

BD = 6

So, BC = 12 as BC = 2BD

By Pythagoras Theorem in ΔABC,

AC2 = BC2 – AB2

AC2 = 144 – 100

AC = 2√11

Option (d) is correct.

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