Q. 65.0( 1 Vote )

In figure 7.25, AC is the length of a pole standing vertical on the ground. The pole is bent at point B, so that the top of the pole touches the ground at a point 15 meters away from the base of the pole. If the length of the pole is 25, find the length of the upper part of the pole.


Answer :

Let the length of upper part of pole be x,



The length of AB becomes 25 – x.


Applying Pythagoras theorem in ΔABC,


(AC’)2 = AB2 + (BC’)2


x2 = (25 – x)2 + 152


x2 = 625 + x2 – 50x + 225


50x = 850


x = 17 m


The length of the upper part of the pole is 17 meters.


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