Q. 5 G4.6( 11 Votes )
cot θ tan (90° -θ
Answer :
Consider L.H.S.
= cot θ tan (90° -θ) - sec (90° - θ)cosec θ +√3tan 12°tan 60°tan 78°
= cot θ cot θ - cosec θ cosec θ +√3 tan 60° tan 12° tan 78°
= cot2 θ – cosec2 θ +√3 tan 60° tan 12° tan(90-12)°
= - (cosec2 θ - cot2 θ) +√3 tan 60° tan 12° cot 12°
= - 1 + √3(√3 × tan 12° cot 12°)
= - 1 + √3(√3 × 1)
= - 1 + 3
= 2 = R.H.S.
Hence, proved.
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