Q. 2

Here,

Now, we have to find adj A and for that we have to find co-factors:

a11 (co – factor of 3) = (-1)1+1(2) = (-1)2(2) = 2

a12 (co – factor of -5) = (-1)1+2(-1) = (-1)3(-1) = 1

a21 (co – factor of -1) = (-1)2+1(-5) = (-1)3(-5) = 5

a22 (co – factor of 2) = (-1)2+2(3) = (-1)4(3) = 3

Now, adj A = Transpose of co-factor Matrix

= I

= I

Calculating |A|.I

= [3 × 2 – (-1) × (-5)]I

= [6 – (5)] I

= (1)I

= I

Hence Proved

Ans.

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