Q. 1

# , , are the medians of ΔABC. If BE = 12, CF = 9 and AB2 + BC2 + AC2 = 600, BC = 10, find AD.

From the given info,

As AB2 + BC2 + AC2 = 600

and BC = 10,

AB2 + AC2 = 500 ...... (1)

BD = 5 ...... (2)

In Δ ABC, using the theorem of Apolloneous, we know that,

For AD to be the median, we have,

AB2 + AC2 = 2(AD2 + BD2)

Substituting values for (1) and (2) in above equation,

500 = 2 (AD2 + 52)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
A Peep into Pythagoras Theorem43 mins
History of Pythagoras and His Theorem37 mins
Quiz | Criterion of Similarity of Triangle45 mins
Foundation | Sum of the Series43 mins
Basics of Binomial Theorem39 mins
Basic Proportionality Theorem44 mins
Basic Proportionality Theorem34 mins
Champ Quiz | Thales Theorem49 mins
NCERT | Fundamental Theorem Of Arithmetic45 mins
Fundamental Theorem of Arithmetic-238 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses