Answer :
From the given info,
As AB2 + BC2 + AC2 = 600
and BC = 10,
⇒ AB2 + AC2 = 500 ...... (1)
As AD is median,
⇒ BD = 5 ...... (2)
In Δ ABC, using the theorem of Apolloneous, we know that,
For AD to be the median, we have,
AB2 + AC2 = 2(AD2 + BD2)
Substituting values for (1) and (2) in above equation,
⇒ 500 = 2 (AD2 + 52)
⇒ 250 = AD2 + 25
⇒ AD2 = 225
⇒ AD2 = 152
⇒ AD = 15
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