Q. 1

# , , are the medians of ΔABC. If BE = 12, CF = 9 and AB2 + BC2 + AC2 = 600, BC = 10, find AD.

From the given info, As AB2 + BC2 + AC2 = 600

and BC = 10,

AB2 + AC2 = 500 ...... (1) BD = 5 ...... (2)

In Δ ABC, using the theorem of Apolloneous, we know that,

For AD to be the median, we have,

AB2 + AC2 = 2(AD2 + BD2)

Substituting values for (1) and (2) in above equation,

500 = 2 (AD2 + 52)

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