Q. 94.7( 11 Votes )
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Draw a less than type ogive for the given data. Hence, obtain the median weight from the graph and verify the result by using the formula.
Less than method:
It is given that on x-axis upper class limit and on y-axis cumulative frequency. We plot the points: (38,0); (40,3); (42,5); (49,9); (46,14); (48,28); (50,32); (52,35)
More than method:
X -axis lower class limit and y-axis cumulative frequency, we plot the points: (38,35); (40,32); (42,30); (44,26); (46,21); (48,7); (50,3)
We find the two types of cumulative frequency curves intersect at point P.
The value of M is 46.5 kg
Now, N = 35
Therefore, = = 17.5
The cumulative frequency is just greater than is 28 and the corresponding classes 46-48
Thus, 46-48 is the median class such that,
l = 46, f = 14, C1 = 14 and h = 2
Median = l + * h
= 46 + * 2
= 46 + = 46 + 0.5
= 46.5 kg
Rate this question :
If the median of the following frequency distribution is 32.5. Find the values of f1 and f2.
The marks obtained by 100 students of a class in an examination are given below.
Draw ‘a less than’ type cumulative frequency curves (orgive). Hence find median.Mathematics - Board Papers
The following distribution gives the daily income of 50 workers of a factory.
Convert the distribution to a ‘less than type’ cumulative frequency distribution and draw its ogive.
The table below shows the daily expenditure on food of 25 households in a locality
Find the mean daily expenditure on food by a suitable methodMathematics - Board Papers