Answer :

Let

x = A(x - 1)(x + 2) + B(x + 2) + C( x – 1)2 …(1)


Substituting x = -1 in equation (1), we get,


B =


Equating the coefficients of x2 and constant term, we get,


A + C = 0


-2A + 2B + C = 0


A = and c =


Thus,







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