# The sum of the squares of three consecutive positive integers is 50. Find the integers.

Let the first number be ‘X’, so the other numbers will be ’(X+1)’ & ‘(X+2).

X2 + (X + 1)2 + (X + 2)2 = 50

X2 + X2 + 1 + 2X + X2 + 4 + 4X = 50

On simplifying further,

3X2 + 6X– 45 = 0

X2 + 2X – 15 = 0

On applying Sreedhracharya formula     X = – 5 or 3

X = 3 (Only Positive values)

X + 1 = 4

X +2 = 5

The numbers are 3, 4 & 5.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Get To Know About Quadratic Formula42 mins  Quiz | Knowing the Nature of Roots44 mins  Take a Dip Into Quadratic graphs32 mins  Foundation | Practice Important Questions for Foundation54 mins  Nature of Roots of Quadratic Equations51 mins  Getting Familiar with Nature of Roots of Quadratic Equations51 mins  Quadratic Equation: Previous Year NTSE Questions32 mins  Champ Quiz | Quadratic Equation33 mins  Understand The Concept of Quadratic Equation45 mins  Balance the Chemical Equations49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 