Q. 65.0( 2 Votes )

The sum of the squares of three consecutive positive integers is 50. Find the integers.

Answer :

Let the first number be ‘X’, so the other numbers will be ’(X+1)’ & ‘(X+2).


X2 + (X + 1)2 + (X + 2)2 = 50


X2 + X2 + 1 + 2X + X2 + 4 + 4X = 50


On simplifying further,


3X2 + 6X– 45 = 0


X2 + 2X – 15 = 0


On applying Sreedhracharya formula







X = – 5 or 3


X = 3 (Only Positive values)


X + 1 = 4


X +2 = 5


The numbers are 3, 4 & 5.


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