Q. 504.8( 5 Votes )

Two pipes running together can fill a cistern in minutes. If one pipe takes 3 minutes more than the other to fill the cistern, find the time in which each pipe would fill the cistern.

Answer :

Let the first pipe fill the cistern in ‘X’ minutes, then the second pipe requires ‘(X+3)’ minutes to fill it.


Applying the concept of Unitary Method,


In one minute, both pipes will fill the part of cistern as below:





80X + 120 = 13X2 + 39X


13X2 – 41X – 120 = 0


On applying Sreedhracharya formula







X = or X = 5


The time required to fill the cistern is 5 & 8 minutes respectively. (as only positive values are considered).


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