Q. 504.8( 5 Votes )

Two pipes running together can fill a cistern in minutes. If one pipe takes 3 minutes more than the other to fill the cistern, find the time in which each pipe would fill the cistern.

Answer :

Let the first pipe fill the cistern in ‘X’ minutes, then the second pipe requires ‘(X+3)’ minutes to fill it.

Applying the concept of Unitary Method,

In one minute, both pipes will fill the part of cistern as below:

80X + 120 = 13X2 + 39X

13X2 – 41X – 120 = 0

On applying Sreedhracharya formula

X = or X = 5

The time required to fill the cistern is 5 & 8 minutes respectively. (as only positive values are considered).

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