# Two pipes running together can fill a cistern in minutes. If one pipe takes 3 minutes more than the other to fill the cistern, find the time in which each pipe would fill the cistern.

Let the first pipe fill the cistern in ‘X’ minutes, then the second pipe requires ‘(X+3)’ minutes to fill it.

Applying the concept of Unitary Method,

In one minute, both pipes will fill the part of cistern as below:

80X + 120 = 13X2 + 39X

13X2 – 41X – 120 = 0

On applying Sreedhracharya formula

X = or X = 5

The time required to fill the cistern is 5 & 8 minutes respectively. (as only positive values are considered).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Knowing the Nature of Roots44 mins
Take a Dip Into Quadratic graphs32 mins
Foundation | Practice Important Questions for Foundation54 mins
Nature of Roots of Quadratic EquationsFREE Class
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Quadratic Equation: Previous Year NTSE Questions32 mins
Champ Quiz | Quadratic Equation33 mins
Balance the Chemical Equations49 mins
Champ Quiz | Quadratic Equation48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses