Q. 414.6( 20 Votes )

Seven years ago Varun's age was five times the square of Swati's age. Three years hence, Swati's age will be two–fifth of Varun's age. Find their present ages.

Answer :

Let seven years, age of Swati was x years and age of Varun was years.


Present age of Swati = (x + 7) years


Present age of Varun = (5x2 + 7) years


Given, after 3 years swati's age will be th of Varun's age.


Age of Swati after 3 years = (x + 7 + 3) years = (x + 10) years


Age of Varun after 3 years = (5x2 + 7 + 3) years = (5x2 + 10) years


Given, age of Swati after 3 years = Two–fifths age of varun after 3 years



(x + 10) = 2(x2 + 2)


x + 10 = 2x2 + 4


2x2 – x + 4 – 10 = 0


2x2 – x – 6 = 0


2x2 – 4x + 3x – 6 = 0


2x(x – 2) + 3(x – 2) = 0


x = 2 [ Age can't be negative ]


Therefore, the present age of Swati = (2 + 7) = 9 year and the present age of Varun = 5(2)2+7=27 years.


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