Q. 394.0( 3 Votes )
If a boy's age and his father's age amount together to 24 years. Fourth pan i product of their ages exceeds the boy's age by 9 years. Find how old they are?
Let the father and his son’s age be ‘X’ yrs and ’(24–X)’ yrs respectively.
As per the question,
24X – X2 – 96 + 4X = 36
X2 – 28X + 132 = 0
X2 – 22X – 6X + 132 = 0
X(X – 22) – 6(X – 22) = 0
(X – 6)(X – 22) = 0
∴X = 22 & boy’age is 2 years.
∴X = 6 & boy’age is 18 years. (practically not possible)
The age of father and his son are 22 years & 2 years respectively.
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