# If a boy's age and his father's age amount together to 24 years. Fourth pan i product of their ages exceeds the boy's age by 9 years. Find how old they are?

Let the father and his son’s age be ‘X’ yrs and ’(24–X)’ yrs respectively.

As per the question, 24X – X2 – 96 + 4X = 36

X2 – 28X + 132 = 0

X2 – 22X – 6X + 132 = 0

X(X – 22) – 6(X – 22) = 0

(X – 6)(X – 22) = 0

X = 22 & boy’age is 2 years.

X = 6 & boy’age is 18 years. (practically not possible) The age of father and his son are 22 years & 2 years respectively.

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