# The denominator of a fraction exceeds its numerator by 3. If one is added to both numerator and denominator, the difference between the new and the original fractions 1 becomes . Find the original fraction.

Let the denominator be ‘(X+3)’, so the numerator will be ‘X’. the original fraction is  the new fraction is  On simplifying further, 24(3) = X2 + 7X + 12

X2 + 7X – 60 = 0 –––––– (i)

On applying Sreedhracharya formula     X = –12 or 5.

the numerator is X = 5 and denominator (X+3) will be 8 and the fraction will be , as taking (–12) will form a fraction i.e., (not satisfying the conditions) .

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