Q. 18

# Integrate the rational functions. Now, Let 4x2 + 10 = (Ax + B)(x2 + 4) + (Cx + D)(x2 + 3)

4x2 + 10 = Ax3 + 4Ax + Bx2 + 4B + Cx3 + 3Cx + Dx2 + 3D

4x2 + 10 = (A+C)x3 + (B + D)x2 + (4A + 3C)x + (4B + 3D)

Equating the coefficients of x3, x2, x and constant term, we get,

A + C = 0

B + D = 0

4A + 3C = 0

4B + 3 B = 0

On solving these equations, we get,

A = 0, B = -2, C = 0 and D = 6

Therefore,      Rate this question :

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