Answer :


Let


1 = A(x-1)(x2+1) + B(x+1)(x2+1) + (Cx + D)(x2 - 1)


1 = A(x3 + x – x2 -1) + B(x3 + x + x2 + 1) + Cx3 + Dx2 - Cx - D


1 = (A + B + C)x3 + (-A + B + D)x2 + (A + B - C)x + (-A + B - D)


Equating the coefficients of x3, x2, x and constant term, we get,


(A + B + C) = 0


(-A + B + C) = 0


(A + B - C) = 0


(-A + B - D) = 0


On solving these equations, we get,


A =


Therefore,






Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USRD Sharma - Volume 2

<img width=Mathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate thMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1