Q. 144.4( 7 Votes )

100 surnames were

Answer :



Mean= =


We have, N= 100,


N/2 = 50


Hence, median class =7-10, such that


l=7, f’=40, f=36, h=3


Median = l +


Here, we may observe that maximum class frequency is 40 belonging to the class interval 7-10


So, modal class= 7-10


Lower limit, l= 7


f0=30, f2=16, f=40,h = 3



=


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