Q. 144.4( 7 Votes )

100 surnames were

Answer :

Mean= =

We have, N= 100,

N/2 = 50

Hence, median class =7-10, such that

l=7, f’=40, f=36, h=3

Median = l +

Here, we may observe that maximum class frequency is 40 belonging to the class interval 7-10

So, modal class= 7-10

Lower limit, l= 7

f0=30, f2=16, f=40,h = 3


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