# Integrate the functions.

Now, Let us consider

Let x2 + 2x + 3 = t

(2x + 2)dx = dt

… (1)

And, now let us consider

x2 + 2x + 3 = x2 + 2x + 1 + 2 = (x +1)2 + (2

Using eq. (1) and (2), we get,

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