It is given in the question that:
∠PBC < ∠QCB
∠ABC + ∠PBC = 180o (linear pair)
∠ABC = 180o - ∠PBC
∠ACB + ∠QCB = 180o(linear pair)
∠ACB = 180o - ∠QCB
∠PBC < ∠QCB therefore,
∠ABC > ∠ACB
Thus,Now the side opposite to larger angle is larger than the side opposite to a smaller angle.
AC > AB as sides opposite to the larger angle is larger.
Rate this question :
Each question conRS Aggarwal & V Aggarwal - Mathematics
In the given figuRS Aggarwal & V Aggarwal - Mathematics