Answer :

It is given in the question that:

∠PBC < ∠QCB

Now,

∠ABC + ∠PBC = 180^{o} (linear pair)

∠ABC = 180^{o} - ∠PBC

Also,

∠ACB + ∠QCB = 180^{o}(linear pair)

∠ACB = 180^{o} - ∠QCB

Since,

∠PBC < ∠QCB therefore,

∠ABC > ∠ACB

Thus,

Now the side opposite to larger angle is larger than the side opposite to a smaller angle.**AC > AB as sides opposite to the larger angle is larger.**

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