# In Fig. 7.48, sid

It is given in the question that:

PBC < QCB

Now,

ABC + PBC = 180o (linear pair)

ABC = 180o - PBC

Also,

ACB + QCB = 180o(linear pair)

ACB = 180o - QCB

Since,

PBC < QCB therefore,

ABC > ACB

Thus,

Now the side opposite to larger angle is larger than the side opposite to a smaller angle.

AC > AB as sides opposite to the larger angle is larger.

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