# Integrate the fun

Let 5x - 2 = 5x - 2 = A(2 + 6x) + B

Now, equating the coefficients of x and constant term on both sides, we get,

6A = 5

A = 2A + B = -2

B = 5x - 2 = (2 + 6x) +   Now, Let 1+2x+3x2 = t

(2 + 6x)dx = dt = log|1+2x+3x2| …(1)

And 1+2x+3x2 =      …(2)

Thus, from (1) and (2), we get,  Rate this question :

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