Q. 123.8( 4 Votes )

The median of the

Answer :


Given, Median = 525


Then median class = 500-600


l = 500, f = 20, F = 36 + f1, h = 100


Median = l +


525 = 500 + * 100


525 – 500 = * 100


25 = (14 – f1) 5


5f1 = 45


f1 = 9


Given, sum of frequencies = 100


= 2 + 5 + f1 + 12 + 17 + 20 + f2 + 9 + 7 + 4 = 100


= 2 + 5 + 9 + 12 + 17 + 20 + f2 + 9 + 7 + 4 = 100


=85 + f2 = 100


f2 = 15


Therefore, f1 = 9 and f2 = 15


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