Q. 11 D5.0( 1 Vote )

Find the values of k, for which the given equation has real roots:

kx2 – 2√5x + 4 = 0

Answer :

Roots are equal

d = 0

d = b2 – 4ac

d = (–2√5)2 – 4 (k) (4)

d = 20 – 16k

Put d = 0

0 = 20 – 16k

16k = 20

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Get To Know About Quadratic Formula42 mins
Quiz | Knowing the Nature of Roots44 mins
Take a Dip Into Quadratic graphs32 mins
Foundation | Practice Important Questions for Foundation54 mins
Nature of Roots of Quadratic Equations51 mins
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Quadratic Equation: Previous Year NTSE Questions32 mins
Understand The Concept of Quadratic Equation45 mins
Champ Quiz | Quadratic Equation33 mins
Quiz | Lets Solve Imp. Qs of Quadratic Equation43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses